If $d(n) \ge (1+\epsilon)log(n)$ some $\epsilon \ge 0$ and $\frac{d(n)}{n} \rightarrow 0$:
then for large n, average path length and diameter of this G(n, p) graph are approximately proportional to $\frac{log(n)}{log(d)}$
$$\frac{AvgDist(n)}{log(n) / log(d(n))} \rightarrow ^p 1$$
same for diameter
n = 6.7 billion (world population)
d = 50(friends, relatives...)
log(n)/log(d) is about 6!
Add Health data set
Schools vary in average degree and homophily
Does diameter match log(n)/log(d)?
Number of links in co-authorship network to Erdos
Had 509 co-authors, more than 1400 papers
2004 auction of co-authorship with William Tozier (Erdos #=4) on E-Bay, winner paid > 1000$
HS Friendships (CJP 09) 6.5
Romances (BMS 03) 0.8
Borrowing (BCDJ 12) 3.2
Co-authors (Newman 01, GLM 06)
Facebook (Marlow 09) 120